-25x^2+35x=0

Solution for -25x^2+35x=0 equation:

-25x^2+35x=0

a = -25; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-25)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-25}=\frac{-70}{-50}
=1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-25}=\frac{0}{-50}
=0
$